When a repair buys time: a 24-month worked example
A €120 repair can be useful even when it is only a bridge. Compare the whole plan, including a later replacement, and keep the payment timing visible.
A repair that buys time can be a sensible choice. Price the time it buys together with what you plan to do next. Comparing the repair bill alone with a replacement bought today leaves out an important part of that decision.
This worked example uses invented amounts and a hypothetical nine-month bridge. Nine months is a planning assumption, not a measured repair lifespan or a promise from a provider. The same applies to the replacement’s assumed use. No phone, repair quote or retailer offer below has been tested or observed.
Start with one period and two complete plans
Imagine that you need a usable phone for the next 24 months. The current device has a fault. For this example, a provider’s complete installed repair quote is €120, with €15 of separate delivery costs. You plan to replace the phone in month nine for an assumed €500 delivered, then use that replacement for the rest of the period.
The alternative is to buy a replacement now for €550 delivered. You assume you can receive €80, after fees, for the current phone in its present condition. You allow no further spending in that replacement plan. These are explicit assumptions, including the zero; an unknown amount would stay blank.
Both replacement amounts include the costs needed to put those hypothetical phones into use. We assume no resale proceeds on the repair path and no other costs. Your real plans may need different entries.
| Spending over 24 months | Repair now, replace in month nine | Replace now |
|---|---|---|
| Installed repair | €120 | — |
| Separate immediate repair costs | €15 | — |
| Replacement checkout today | — | €550 |
| Current-phone proceeds | None assumed | −€80 |
| Later spending | €500 | €0 |
| Planned net cash cost | €635 | €470 |
The sums are €120 + €15 + €500 = €635 and €550 − €80 + €0 = €470. The repair-then-replace plan has €165 more net spending in this scenario. That result depends on every assumption in the table, particularly the later €500 purchase and the €80 proceeds.
Payment timing can change the practical choice
The repair route needs €135 initially, followed by the assumed €500 in month nine. Buying now needs a €550 checkout payment. If the €80 from selling the old phone arrives later, it cannot pay today’s checkout bill.
A person who cannot comfortably spend €550 now may reasonably value the bridge. That does not turn €635 into €470; it means cash availability matters alongside the total. Write down when each payment and receipt would happen. This worksheet adds nominal cash amounts and does not value the timing of money or calculate financing charges.
There is another difference: at month 24, the two replacement phones have been owned for different lengths of time. Their remaining values are excluded from this cash comparison. A lower spending total alone cannot establish which plan gives better overall value.
Test the assumption that changes the answer
Suppose you instead plan to keep the repaired phone for the entire 24 months, with no later spending. Only under that alternative assumption, the repair plan becomes €120 + €15 + €0 = €135, which is €335 below €470.
That is not evidence that the repair will last 24 months. You need a diagnosis, a clear description of the work and a realistic account of what the phone must do. Ask what remains uncertain. If you cannot yet judge whether the plan covers the full period, keep the worksheet’s coverage answer uncertain.
With the other figures unchanged, €335 of later repair-path spending would bring the two plans level: €135 + €335 = €470. Use that as a question to investigate, not a universal repair-price limit. A different replacement price, sale amount or planning period changes the threshold.
Put the example into the worksheet
Open the repair worksheet and choose 24 months. For the first scenario, enter:
- Quoted repair amount: 120; choose the complete quote option only because that is an explicit assumption in this example.
- Other immediate repair costs: 15.
- Later spending in the repair plan: 500.
- Replacement checkout total: 550.
- Old-phone proceeds: 80.
- Later spending in the replacement plan: 0.
The example assumes both plans cover the period. In your own worksheet, confirm that only after reviewing your actual plan. A parts-only price remains incomplete. If a trade-in credit has already reduced the checkout amount you entered, do not subtract that credit again as proceeds.
You can save incomplete figures and return with the missing information. The worksheet saves one plan in the current browser; My FixIndex keeps your phone checks separately.
Gather the evidence before committing
Ask the repair provider to identify the fault, included work, complete price, timing and repair terms. Review the manufacturer’s current software-support guidance for each device; Google’s Pixel support page is one example of the source to consult for the relevant model. A chosen 24-month period is not proof of support or reliability.
Use My FixIndex to record your own checks and next review date, and repair options to prepare the questions you need answered. If replacement remains useful, inspect the exact model, condition and checkout total using our worked buying example.
Our view: a repair can be worthwhile because it resolves a fault, preserves a useful phone or lets you choose a better time to replace it. Give that purpose a complete spending plan. Neither a cheap repair nor a low comparison total can make an unsupported assumption reliable.
Some linked model pages contain marked retailer links that may earn FixIndex a commission. This example has no paid placement or live offer. Read the affiliate disclosure and Brief 001 for the rest of this edition.
How shop links work: Affiliate disclosure.